Interarrival times is exponentially distributed with mean $E[X] = 10 = 1/\lambda$. Hence $\lambda = 0.1$.
For part 1, we need at least 10 requests within one hour. Implies that the sum of the first 10 interarrival times should be less than 60 minutes. \begin{align} P(T_{1} + \cdots + T_{10} < 60) \end{align} We know that the sum of independent exponential variables is Gamma distribution. Hence, \begin{align} P(Gamma(10, 0.1) < 60) = 0.08392 \end{align}
Similar to the above part, we need the sum of first 10 interarrival times to be more than two hours \begin{align} P(T_{1} + \cdots + T_{10} \geq 120) = P(Gamma(10, 0.1) \geq 120) = 0.24239 \end{align}