Answer¶
We can rewrite the equation in the usual format as
\[
\begin{aligned}
\difftwo{u} + \roundbr{-2x^{2}}u = -\sin x
\end{aligned}
\]
Hence, the equation is Linear, of order 2, degree 1, and nonhomogenous (because $r(x) = \sin x$).
We can rewrite the equation in the usual format as
Hence, the equation is Linear, of order 2, degree 1, and nonhomogenous (because $r(x) = \sin x$).